Geometry of Cuts and Metrics
M.M. Deza and M. Laurent,
Springer, 1997
To correct Proposition 10.2.1, one must replace (iii) by:
The implication (iii') ==> (ii) is now clear. For the implication (ii) ==> (iii'), use the fact that, if $D$ is a matrix of negative type and $B$ is a positive semidefinite matrix with $Be=0$, then $\sum_{i,j}B_{ij}D_{ij} \le 0$. To see it,
write $B=bb^T + cc^T + ... $ for some vectors $b,c,...$ with $b^Te=c^Te=...=0$,
and note that $\sum_{i,j}b_ib_jD_{ij} \le 0$ for any real vector $b$ with $b^Te=0$ (using a continuity argument).
(iii') For every positive semidefinite matrix $B$ with $Be=0$, the inequality (10.2.5) holds.
Proof of Theorem 11.1.21: the current argument for the implications (iv)==>(ii) and (iii)==>(ii) is not correct. The proof goes as follows. Assume that (ii) does not hold. Suppose first that $d$ is not totally decomposable. Then, by Fact 11.1.13, the path metric of $K_{2,3}$) is
a minor of $d$. Therefore, the path metric of $K_3$ is a minor of $d$, thus violating (iv).
Condition (iii) is violated as well, since
$d(K_3)$ is not $l_1^1$-embeddable and using Lemma 11.1.18.
The rest of the proof is correct.
Thanks in advance for mailing me further corrections.